38. Count and Say
Description
The count-and-say sequence is a sequence of digit strings defined by the recursive formula:
countAndSay(1) = "1"countAndSay(n)is the way you would "say" the digit string fromcountAndSay(n-1), which is then converted into a different digit string.
To determine how you "say" a digit string, split it into the minimal number of groups so that each group is a contiguous section all of the same character. Then for each group, say the number of characters, then say the character. To convert the saying into a digit string, replace the counts with a number and concatenate every saying.
For example, the saying and conversion for digit string "3322251":
Given a positive integer n, return the nth term of the count-and-say sequence.
Constraints
1 <= n <= 30
Approach
Links
GeeksforGeeks
ProgramCreek
YouTube
Examples
Input: n = 1
Output: "1"
Explanation: This is the base case.
Input: n = 4
Output: "1211"
Explanation:
countAndSay(1) = "1"
countAndSay(2) = say "1" = one 1 = "11"
countAndSay(3) = say "11" = two 1's = "21"
countAndSay(4) = say "21" = one 2 + one 1 = "12" + "11" = "1211"
Input: n = 10
Output: "13211311123113112211"
Input: n = 20
Output: "11131221131211132221232112111312111213111213211231132132211211131221131211221321123113213221123113112221131112311332211211131221131211132211121312211231131112311211232221121321132132211331121321231231121113112221121321133112132112312321123113112221121113122113121113123112112322111213211322211312113211"
Solutions
/**
* Time complexity :
* Space complexity :
*/
class Solution {
public String countAndSay(int n) {
if(n < 2) {
return n == 0? "": "1";
}
StringBuilder result = new StringBuilder("11");
while(n-- > 2) {
StringBuilder curr = new StringBuilder();
int len = result.length(), count = 1;
for(int i = 1; i < len; i++) {
if(result.charAt(i-1) == result.charAt(i)) {
count++;
} else {
curr.append(count).append(result.charAt(i-1));
count = 1;
}
}
curr.append(count).append(result.charAt(len-1));
result = curr;
}
return result.toString();
}
}Follow up
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