1464. Maximum Product of Two Elements in an Array
Description
Given the array of integers nums
, you will choose two different indices i
and j
of that array. Return the maximum value of (nums[i]-1)*(nums[j]-1)
.
Constraints
2 <= nums.length <= 500
1 <= nums[i] <= 10^3
Approach
Links
GeeksforGeeks
ProgramCreek
YouTube
Examples
Input: nums = [3, 4, 5, 2]
Output: 12
Explanation: If you choose the indices i=1 and j=2 (indexed from 0), you will get the maximum value, that is, (nums[1]-1)(nums[2]-1) = (4-1)(5-1) = 3*4 = 12.
Solutions
/**
* Time complexity :
* Space complexity :
*/
class Solution {
public int maxProduct(int[] nums) {
if(nums == null || nums.length < 2) {
return 0;
}
int max1 = 0, max2 = 0;
for(int num: nums) {
if(num > max1) {
max2 = max1;
max1 = num;
} else if(num > max2) {
max2 = num;
}
}
return (max1-1)*(max2-1);
}
}
Follow up
Previous1461. Check If a String Contains All Binary Codes of Size KNext1480. Running Sum of 1d Array
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