300. Longest Increasing Subsequence

Description

Given an integer array nums, return the length of the longest strictly increasing subsequence.

A subsequence is a sequence that can be derived from an array by deleting some or no elements without changing the order of the remaining elements. For example, [3,6,2,7] is a subsequence of the array [0,3,1,6,2,2,7].

Constraints

• 1 <= nums.length <= 2500

• -104 <= nums[i] <= 104

Approach

Links

• Binarysearch

• GeeksforGeeks

• Leetcode

• ProgramCreek

• YouTube

Examples

Example 1

Input: nums = [10, 9, 2, 5, 3, 7, 101, 18]

Output: 4

Explanation: The longest increasing subsequence is [2, 3, 7, 101], therefore the length is 4.

Example 2

Input: nums = [0, 1, 0, 3, 2, 3]

Output: 4

Example 3

Input: nums = [7, 7, 7, 7, 7, 7, 7]

Output: 1

Solutions

Solution 1

/**
 * Time complexity : 
 * Space complexity : 
 */

class Solution {
    public int lengthOfLIS(int[] nums) {
        if(nums == null || nums.length == 0) {
            return 0;
        }
        int n = nums.length, maxLen = 1;
        int[] dp = new int[n];
        Arrays.fill(dp, 1);
        
        for(int i = 1; i < n; i++) {
            for(int j = 0; j < i; j++) {
                if(nums[i] > nums[j] && dp[j]+1 > dp[i]) {
                    dp[i] = dp[j]+1;
                }
            }
            if(dp[i] > maxLen) {
                maxLen = dp[i];
            }
        }
        return maxLen;
    }
}

Follow up

• Can you come up with an algorithm that runs in O(n log(n)) time complexity?