109. Convert Sorted List to Binary Search Tree
Description
Given the head
of a singly linked list where elements are sorted in ascending order, convert it to a height balanced BST.
For this problem, a height-balanced binary tree is defined as a binary tree in which the depth of the two subtrees of every node never differ by more than 1.

Constraints
The numner of nodes in
head
is in the range[0, 2 * 10^4]
.-10^5 <= Node.val <= 10^5
Approach
Links
YouTube
Examples
Input: head = [-10, -3, 0, 5, 9]
Output: [0, -3, 9, -10, null, 5]
Explanation: One possible answer is [0, -3, 9, -10, null, 5], which represents the shown height balanced BST.
Solutions
// Definition for singly-linked list.
public class ListNode {
int val;
ListNode next;
ListNode() {}
ListNode(int val) { this.val = val; }
ListNode(int val, ListNode next) {
this.val = val;
this.next = next;
}
}
Follow up
Last updated
Was this helpful?