478. Generate Random Point in a Circle
Description
Given the radius and x-y positions of the center of a circle, write a function randPoint
which generates a uniform random point in the circle.
Note:
input and output values are in floating-point.
radius and x-y position of the center of the circle is passed into the class constructor.
a point on the circumference of the circle is considered to be in the circle.
randPoint
returns a size 2 array containing x-position and y-position of the random point, in that order.
Explanation of Input Syntax:
The input is two lists: the subroutines called and their arguments. Solution
's constructor has three arguments, the radius, x-position of the center, and y-position of the center of the circle. randPoint
has no arguments. Arguments are always wrapped with a list, even if there aren't any.
Constraints
Approach
Links
GeeksforGeeks
ProgramCreek
YouTube
Examples
Input:
["Solution", "randPoint", "randPoint", "randPoint"]
[[1, 0, 0], [], [], []]
Output: [null, [-0.72939, -0.65505], [-0.78502, -0.28626], [-0.83119, -0.19803]]
Solutions
/**
* Time complexity :
* Space complexity :
*/
class Solution {
private static final Random random = new Random();
private double radius;
private double x_center;
private double y_center;
public Solution(double radius, double x_center, double y_center) {
this.radius = radius;
this.x_center = x_center;
this.y_center = y_center;
}
public double[] randPoint() {
double r = Math.sqrt(random.nextDouble()) * radius;
double theta = random.nextDouble() * 2 * Math.PI;
return new double[]{
x_center + r * Math.cos(theta),
y_center + r * Math.sin(theta)
};
}
}
/**
* Your Solution object will be instantiated and called as such:
* Solution obj = new Solution(radius, x_center, y_center);
* double[] param_1 = obj.randPoint();
*/
Follow up
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